7(b-2)+3=2(b+3)+3

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Solution for 7(b-2)+3=2(b+3)+3 equation: 



7(b-2)+3=2(b+3)+3

We move all terms to the left:

7(b-2)+3-(2(b+3)+3)=0

We multiply parentheses

7b-(2(b+3)+3)-14+3=0



We calculate terms in parentheses: -(2(b+3)+3), so:

2(b+3)+3

We multiply parentheses

2b+6+3

We add all the numbers together, and all the variables

2b+9

Back to the equation:

-(2b+9)



We add all the numbers together, and all the variables

7b-(2b+9)-11=0

We get rid of parentheses

7b-2b-9-11=0

We add all the numbers together, and all the variables

5b-20=0

We move all terms containing b to the left, all other terms to the right

5b=20

b=20/5

b=4

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