2(h+1)-2=2(2h+2)

Solution for 2(h+1)-2=2(2h+2) equation:

2(h+1)-2=2(2h+2)

We move all terms to the left:

2(h+1)-2-(2(2h+2))=0

We multiply parentheses

2h-(2(2h+2))+2-2=0


We calculate terms in parentheses: -(2(2h+2)), so:

2(2h+2)

We multiply parentheses

4h+4

Back to the equation:

-(4h+4)


We add all the numbers together, and all the variables

2h-(4h+4)=0

We get rid of parentheses

2h-4h-4=0

We add all the numbers together, and all the variables

-2h-4=0

We move all terms containing h to the left, all other terms to the right

-2h=4

h=4/-2

h=-2