11(l-4)+5=4(l+2)+30

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Solution for 11(l-4)+5=4(l+2)+30 equation: 



11(l-4)+5=4(l+2)+30

We move all terms to the left:

11(l-4)+5-(4(l+2)+30)=0

We multiply parentheses

11l-(4(l+2)+30)-44+5=0



We calculate terms in parentheses: -(4(l+2)+30), so:

4(l+2)+30

We multiply parentheses

4l+8+30

We add all the numbers together, and all the variables

4l+38

Back to the equation:

-(4l+38)



We add all the numbers together, and all the variables

11l-(4l+38)-39=0

We get rid of parentheses

11l-4l-38-39=0

We add all the numbers together, and all the variables

7l-77=0

We move all terms containing l to the left, all other terms to the right

7l=77

l=77/7

l=11

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