3(2q-2)+1=4(q-1)+3

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Solution for 3(2q-2)+1=4(q-1)+3 equation: 



3(2q-2)+1=4(q-1)+3

We move all terms to the left:

3(2q-2)+1-(4(q-1)+3)=0

We multiply parentheses

6q-(4(q-1)+3)-6+1=0



We calculate terms in parentheses: -(4(q-1)+3), so:

4(q-1)+3

We multiply parentheses

4q-4+3

We add all the numbers together, and all the variables

4q-1

Back to the equation:

-(4q-1)



We add all the numbers together, and all the variables

6q-(4q-1)-5=0

We get rid of parentheses

6q-4q+1-5=0

We add all the numbers together, and all the variables

2q-4=0

We move all terms containing q to the left, all other terms to the right

2q=4

q=4/2

q=2

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