2(3y+5)=-4(y+2)

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Solution for 2(3y+5)=-4(y+2) equation: 



2(3y+5)=-4(y+2)

We move all terms to the left:

2(3y+5)-(-4(y+2))=0

We multiply parentheses

6y-(-4(y+2))+10=0



We calculate terms in parentheses: -(-4(y+2)), so:

-4(y+2)

We multiply parentheses

-4y-8

Back to the equation:

-(-4y-8)



We get rid of parentheses

6y+4y+8+10=0

We add all the numbers together, and all the variables

10y+18=0

We move all terms containing y to the left, all other terms to the right

10y=-18

y=-18/10

y=-1+4/5

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