An equation of the type of ax + b = 0 is called a linear equation in one unknown, where a nad b are known numbers and x is an unknown value. To solve this equation means to find the numerical value of x , at which this equation becomes an identity.

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| 3m-7+m+23=26 | | 2x+6=2(2x-4) | | 9j-8=89j | | -47-7n=9n-5(4n+8) | | x/2+1/6=x/(2)-(1)/(4) | | 5(1=4x)=2(3-10x) | | 2x+3+6x=77 | | -24+6x+4=2x-5-x | | 14(p+1)=14 | | (3x(38)-4)=180 | | 4(5x-6)^2-31=5 | | -2(f-1)=2-2f | | 6x+14=-48+44 | | 35=u+6 | | 7x-12=3(x=4) | | (2b+9)=2(b+(9)/(2)) | | -3w+2=24 | | X-5/3=x-2 | | 9x-23=12x+2 | | 2y=30-4y= | | -4-4(-x-1)=-4(3+2x) | | 4x+15=2x-24 | | 31+w/3=21 | | (x)/(2)+(1)/(6)=(x)/(2)-(1)/(4) | | 4d=8d | | 26=7(g-9)+1226=(g-9)+12 | | 2t+-3=5 | | 5d-2d=0 | | 5x-1=4(x+4) | | x/3+4/3=12 | | 6+1x=21 |

| 2/3x+5/3=-4 | | 27x+8=125 | | 45q-38=72q-84 | | 3x+24=-60 | | –30=–2(−n+3) | | (3x-3)=(4x+2) | | (2x=7)(9x-3) | | 2b-12=8 | | 10x+28(x-5)=316 | | 2(4x-5)=4(2x-4) | | (3*35+20)+y=180 | | 3(4n-5)=-87 | | 9=p+7 | | 27x+9=200 | | c-5=5-c | | -5(1+5r)=170 | | 20=4+2p | | 3(9x+8)=(8x-9) | | b+3=3+b | | 6x+3(-2x-7)=9 | | 61-32=n=41 | | 4x+6+42=9x+8 | | −36+6a=−3(a−6) | | 3(x+8)=-3(x+8) | | n-17=13 | | 7/8=d+4/d | | -9=-3(v-2) | | 5(2x=6) | | 2/3m+2=17 | | -x3=-4 | | 175m-125+42,975=45,000-175m | | x-6=80 | | –3x+3=-15+6x | | 31x+5=11x+7=180 |

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