An equation of the type of ax + b = 0 is called a linear equation in one unknown, where a nad b are known numbers and x is an unknown value. To solve this equation means to find the numerical value of x , at which this equation becomes an identity.

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| 6(x²+x)+5=0 | | x+43=-12 | | 4s²-100=0 | | 3x(5x+4)=8 | | 12x-15=11x | | 3x^2-1/75=0 | | d²-5d=0 | | 4x-45=7x-9 | | 1350-15x=3x | | 2x+3(3x)=106 | | 4x-45=7(×-9) | | 2x+3x+3=106 | | 16x2=-9 | | 11u-3u=48 | | 3^(3x-9)=27 | | (1/3)*x-4=(2/3)*(3*x-2) | | 2+3x=154 | | x^@-10x+25=0 | | X2-5x+6x=0 | | 8+2w=2 | | 5k-4/2=2 | | (-4+-3x)(12+-1x)=0 | | (3x+4)+(x-12)=0 | | (3x+4)-(x-12)=0 | | 25/5x+x=36 | | 3x-24=-9(x+8) | | Y=103x2+99.99x-20.86 | | -7x-16=-2(x+3) | | 6/7*t=-24 | | P=30x-200-(20x+200) | | 20x²-200x-130=0 |

| x-x/10=158378 | | x-x/10=76582 | | x-x/10=69673 | | 1/3x+4=2/3(3x-2) | | (4x^2+30x+31)/(x+6)=0 | | 5t2-5t-98=0 | | 7(3x+10)=6(4x+13) | | 2x²+7x+9=0 | | 3x+26=1x+46 | | ((2/5)x)-3=(4/3)(4x-3) | | (2/5)x-3=(4/3)*(4x-3) | | (3/7)x)-1=((2/3)(6x-2) | | 5p-7-5p=-21 | | 6m+2+(m+7)=m-14 | | (3+2)(7)-5=(x)7-5 | | X+x+15=45 | | b^2-4b+2=0 | | 2v=3v-17 | | 3z-75=z-15 | | -12+20x=78 | | 2s-28=s+79 | | 3(2+(7-5))=3(2+x) | | 2x−27=127 | | x/5=5x= | | y2-7y+104=0 | | x/7=2x= | | 2+9=2z | | 5(f-5)=-15 | | 12^-9y=7 | | (v-1)^2=2v^2+4v-6 | | -1.2(3–x)= | | 6x-6-5=61 | | 9x-7x-7=7 | | 6x+2x+5+3=64 |

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