3(2s-2)-5=3(s+2)+1

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Solution for 3(2s-2)-5=3(s+2)+1 equation: 



3(2s-2)-5=3(s+2)+1

We move all terms to the left:

3(2s-2)-5-(3(s+2)+1)=0

We multiply parentheses

6s-(3(s+2)+1)-6-5=0



We calculate terms in parentheses: -(3(s+2)+1), so:

3(s+2)+1

We multiply parentheses

3s+6+1

We add all the numbers together, and all the variables

3s+7

Back to the equation:

-(3s+7)



We add all the numbers together, and all the variables

6s-(3s+7)-11=0

We get rid of parentheses

6s-3s-7-11=0

We add all the numbers together, and all the variables

3s-18=0

We move all terms containing s to the left, all other terms to the right

3s=18

s=18/3

s=6

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