9(r-4)+8=4(r+3)+15

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Solution for 9(r-4)+8=4(r+3)+15 equation: 



9(r-4)+8=4(r+3)+15

We move all terms to the left:

9(r-4)+8-(4(r+3)+15)=0

We multiply parentheses

9r-(4(r+3)+15)-36+8=0



We calculate terms in parentheses: -(4(r+3)+15), so:

4(r+3)+15

We multiply parentheses

4r+12+15

We add all the numbers together, and all the variables

4r+27

Back to the equation:

-(4r+27)



We add all the numbers together, and all the variables

9r-(4r+27)-28=0

We get rid of parentheses

9r-4r-27-28=0

We add all the numbers together, and all the variables

5r-55=0

We move all terms containing r to the left, all other terms to the right

5r=55

r=55/5

r=11

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