5(t-1)-8=3(t+1)+8

Solution for 5(t-1)-8=3(t+1)+8 equation:

5(t-1)-8=3(t+1)+8

We move all terms to the left:

5(t-1)-8-(3(t+1)+8)=0

We multiply parentheses

5t-(3(t+1)+8)-5-8=0


We calculate terms in parentheses: -(3(t+1)+8), so:

3(t+1)+8

We multiply parentheses

3t+3+8

We add all the numbers together, and all the variables

3t+11

Back to the equation:

-(3t+11)


We add all the numbers together, and all the variables

5t-(3t+11)-13=0

We get rid of parentheses

5t-3t-11-13=0

We add all the numbers together, and all the variables

2t-24=0

We move all terms containing t to the left, all other terms to the right

2t=24

t=24/2

t=12