3(2h+1)+6=2(2h-4)-5

Solution for 3(2h+1)+6=2(2h-4)-5 equation:

3(2h+1)+6=2(2h-4)-5

We move all terms to the left:

3(2h+1)+6-(2(2h-4)-5)=0

We multiply parentheses

6h-(2(2h-4)-5)+3+6=0


We calculate terms in parentheses: -(2(2h-4)-5), so:

2(2h-4)-5

We multiply parentheses

4h-8-5

We add all the numbers together, and all the variables

4h-13

Back to the equation:

-(4h-13)


We add all the numbers together, and all the variables

6h-(4h-13)+9=0

We get rid of parentheses

6h-4h+13+9=0

We add all the numbers together, and all the variables

2h+22=0

We move all terms containing h to the left, all other terms to the right

2h=-22

h=-22/2

h=-11