5(2l-2)-20=20(2l+6)+12

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Solution for 5(2l-2)-20=20(2l+6)+12 equation: 



5(2l-2)-20=20(2l+6)+12

We move all terms to the left:

5(2l-2)-20-(20(2l+6)+12)=0

We multiply parentheses

10l-(20(2l+6)+12)-10-20=0



We calculate terms in parentheses: -(20(2l+6)+12), so:

20(2l+6)+12

We multiply parentheses

40l+120+12

We add all the numbers together, and all the variables

40l+132

Back to the equation:

-(40l+132)



We add all the numbers together, and all the variables

10l-(40l+132)-30=0

We get rid of parentheses

10l-40l-132-30=0

We add all the numbers together, and all the variables

-30l-162=0

We move all terms containing l to the left, all other terms to the right

-30l=162

l=162/-30

l=-5+2/5

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