(7x-14)=(2x+11)+(3x-7)

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Solution for (7x-14)=(2x+11)+(3x-7) equation: 



(7x-14)=(2x+11)+(3x-7)

We move all terms to the left:

(7x-14)-((2x+11)+(3x-7))=0

We get rid of parentheses

7x-((2x+11)+(3x-7))-14=0



We calculate terms in parentheses: -((2x+11)+(3x-7)), so:

(2x+11)+(3x-7)

We get rid of parentheses

2x+3x+11-7

We add all the numbers together, and all the variables

5x+4

Back to the equation:

-(5x+4)



We get rid of parentheses

7x-5x-4-14=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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