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(7x-5)=(3x+3)+(7x-5)
We move all terms to the left:
(7x-5)-((3x+3)+(7x-5))=0
We get rid of parentheses
7x-((3x+3)+(7x-5))-5=0
We calculate terms in parentheses: -((3x+3)+(7x-5)), so:We get rid of parentheses
(3x+3)+(7x-5)
We get rid of parentheses
3x+7x+3-5
We add all the numbers together, and all the variables
10x-2
Back to the equation:
-(10x-2)
7x-10x+2-5=0
We add all the numbers together, and all the variables
-3x-3=0
We move all terms containing x to the left, all other terms to the right
-3x=3
x=3/-3
x=-1
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