(2x+12)=(3x+17)+(10x-1)

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Solution for (2x+12)=(3x+17)+(10x-1) equation:



(2x+12)=(3x+17)+(10x-1)
We move all terms to the left:
(2x+12)-((3x+17)+(10x-1))=0
We get rid of parentheses
2x-((3x+17)+(10x-1))+12=0
We calculate terms in parentheses: -((3x+17)+(10x-1)), so:
(3x+17)+(10x-1)
We get rid of parentheses
3x+10x+17-1
We add all the numbers together, and all the variables
13x+16
Back to the equation:
-(13x+16)
We get rid of parentheses
2x-13x-16+12=0
We add all the numbers together, and all the variables
-11x-4=0
We move all terms containing x to the left, all other terms to the right
-11x=4
x=4/-11
x=-4/11

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