(3x+14)=(2x+12)+(7x+6)

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Solution for (3x+14)=(2x+12)+(7x+6) equation: 



(3x+14)=(2x+12)+(7x+6)

We move all terms to the left:

(3x+14)-((2x+12)+(7x+6))=0

We get rid of parentheses

3x-((2x+12)+(7x+6))+14=0



We calculate terms in parentheses: -((2x+12)+(7x+6)), so:

(2x+12)+(7x+6)

We get rid of parentheses

2x+7x+12+6

We add all the numbers together, and all the variables

9x+18

Back to the equation:

-(9x+18)



We get rid of parentheses

3x-9x-18+14=0

We add all the numbers together, and all the variables

-6x-4=0

We move all terms containing x to the left, all other terms to the right

-6x=4

x=4/-6

x=-2/3

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