(11x-7)=(3x+17)+(3x+11)

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Solution for (11x-7)=(3x+17)+(3x+11) equation: 



(11x-7)=(3x+17)+(3x+11)

We move all terms to the left:

(11x-7)-((3x+17)+(3x+11))=0

We get rid of parentheses

11x-((3x+17)+(3x+11))-7=0



We calculate terms in parentheses: -((3x+17)+(3x+11)), so:

(3x+17)+(3x+11)

We get rid of parentheses

3x+3x+17+11

We add all the numbers together, and all the variables

6x+28

Back to the equation:

-(6x+28)



We get rid of parentheses

11x-6x-28-7=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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