(3x+3)=(7x-5)+(2x+4)

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Solution for (3x+3)=(7x-5)+(2x+4) equation: 



(3x+3)=(7x-5)+(2x+4)

We move all terms to the left:

(3x+3)-((7x-5)+(2x+4))=0

We get rid of parentheses

3x-((7x-5)+(2x+4))+3=0



We calculate terms in parentheses: -((7x-5)+(2x+4)), so:

(7x-5)+(2x+4)

We get rid of parentheses

7x+2x-5+4

We add all the numbers together, and all the variables

9x-1

Back to the equation:

-(9x-1)



We get rid of parentheses

3x-9x+1+3=0

We add all the numbers together, and all the variables

-6x+4=0

We move all terms containing x to the left, all other terms to the right

-6x=-4

x=-4/-6

x=2/3

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