(2x+4)=(3x+3)+(7x-5)

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Solution for (2x+4)=(3x+3)+(7x-5) equation: 



(2x+4)=(3x+3)+(7x-5)

We move all terms to the left:

(2x+4)-((3x+3)+(7x-5))=0

We get rid of parentheses

2x-((3x+3)+(7x-5))+4=0



We calculate terms in parentheses: -((3x+3)+(7x-5)), so:

(3x+3)+(7x-5)

We get rid of parentheses

3x+7x+3-5

We add all the numbers together, and all the variables

10x-2

Back to the equation:

-(10x-2)



We get rid of parentheses

2x-10x+2+4=0

We add all the numbers together, and all the variables

-8x+6=0

We move all terms containing x to the left, all other terms to the right

-8x=-6

x=-6/-8

x=3/4

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