7(b+4)=32b+16+10(24)

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Solution for 7(b+4)=32b+16+10(24) equation: 



7(b+4)=32b+16+10(24)

We move all terms to the left:

7(b+4)-(32b+16+10(24))=0

We add all the numbers together, and all the variables

7(b+4)-(32b+1040)=0

We multiply parentheses

7b-(32b+1040)+28=0

We get rid of parentheses

7b-32b-1040+28=0

We add all the numbers together, and all the variables

-25b-1012=0

We move all terms containing b to the left, all other terms to the right

-25b=1012

b=1012/-25

b=-40+12/25

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