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x=10x(2/5)
We move all terms to the left:
x-(10x(2/5))=0
We add all the numbers together, and all the variables
x-(10x(+2/5))=0
We multiply all the terms by the denominator
x*5))-(10x(+2=0
Wy multiply elements
5x^2+2=0
a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation
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