0=9a-20/3a-4

Solution for 0=9a-20/3a-4 equation:

0=9a-20/3a-4

We move all terms to the left:

0-(9a-20/3a-4)=0


Domain of the equation: 3a-4)!=0

a∈R


We add all the numbers together, and all the variables

-(9a-20/3a-4)=0

We get rid of parentheses

-9a+20/3a+4=0

We multiply all the terms by the denominator


-9a*3a+4*3a+20=0

Wy multiply elements

-27a^2+12a+20=0

a = -27; b = 12; c = +20;
Δ = b2-4ac
Δ = 122-4·(-27)·20
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-48}{2*-27}=\frac{-60}{-54}
=1+1/9
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+48}{2*-27}=\frac{36}{-54}
=-2/3
$