5(b-4)=7b-8+56

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Solution for 5(b-4)=7b-8+56 equation: 



5(b-4)=7b-8+56

We move all terms to the left:

5(b-4)-(7b-8+56)=0

We add all the numbers together, and all the variables

5(b-4)-(7b+48)=0

We multiply parentheses

5b-(7b+48)-20=0

We get rid of parentheses

5b-7b-48-20=0

We add all the numbers together, and all the variables

-2b-68=0

We move all terms containing b to the left, all other terms to the right

-2b=68

b=68/-2

b=-34

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