7(b+4)=14b-8+10

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Solution for 7(b+4)=14b-8+10 equation: 



7(b+4)=14b-8+10

We move all terms to the left:

7(b+4)-(14b-8+10)=0

We add all the numbers together, and all the variables

7(b+4)-(14b+2)=0

We multiply parentheses

7b-(14b+2)+28=0

We get rid of parentheses

7b-14b-2+28=0

We add all the numbers together, and all the variables

-7b+26=0

We move all terms containing b to the left, all other terms to the right

-7b=-26

b=-26/-7

b=3+5/7

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