7(b+4)=32b+15+10(23)

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Solution for 7(b+4)=32b+15+10(23) equation: 



7(b+4)=32b+15+10(23)

We move all terms to the left:

7(b+4)-(32b+15+10(23))=0

We add all the numbers together, and all the variables

7(b+4)-(32b+1038)=0

We multiply parentheses

7b-(32b+1038)+28=0

We get rid of parentheses

7b-32b-1038+28=0

We add all the numbers together, and all the variables

-25b-1010=0

We move all terms containing b to the left, all other terms to the right

-25b=1010

b=1010/-25

b=-40+2/5

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