3(c-5)=4(c+12)

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Solution for 3(c-5)=4(c+12) equation: 



3(c-5)=4(c+12)

We move all terms to the left:

3(c-5)-(4(c+12))=0

We multiply parentheses

3c-(4(c+12))-15=0



We calculate terms in parentheses: -(4(c+12)), so:

4(c+12)

We multiply parentheses

4c+48

Back to the equation:

-(4c+48)



We get rid of parentheses

3c-4c-48-15=0

We add all the numbers together, and all the variables

-1c-63=0

We move all terms containing c to the left, all other terms to the right

-c=63

c=63/-1

c=-63

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