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55=(2x-5)+(2x-5)+x
We move all terms to the left:
55-((2x-5)+(2x-5)+x)=0
We calculate terms in parentheses: -((2x-5)+(2x-5)+x), so:We get rid of parentheses
(2x-5)+(2x-5)+x
We add all the numbers together, and all the variables
x+(2x-5)+(2x-5)
We get rid of parentheses
x+2x+2x-5-5
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
-5x+10+55=0
We add all the numbers together, and all the variables
-5x+65=0
We move all terms containing x to the left, all other terms to the right
-5x=-65
x=-65/-5
x=+13
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