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(4n+6)(8n+8)=0
We multiply parentheses ..
(+32n^2+32n+48n+48)=0
We get rid of parentheses
32n^2+32n+48n+48=0
We add all the numbers together, and all the variables
32n^2+80n+48=0
a = 32; b = 80; c = +48;
Δ = b2-4ac
Δ = 802-4·32·48
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-16}{2*32}=\frac{-96}{64} =-1+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+16}{2*32}=\frac{-64}{64} =-1 $
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