6(2x-3)+11=4(x+7)+x

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Solution for 6(2x-3)+11=4(x+7)+x equation: 



6(2x-3)+11=4(x+7)+x

We move all terms to the left:

6(2x-3)+11-(4(x+7)+x)=0

We multiply parentheses

12x-(4(x+7)+x)-18+11=0



We calculate terms in parentheses: -(4(x+7)+x), so:

4(x+7)+x

We add all the numbers together, and all the variables

x+4(x+7)

We multiply parentheses

x+4x+28

We add all the numbers together, and all the variables

5x+28

Back to the equation:

-(5x+28)



We add all the numbers together, and all the variables

12x-(5x+28)-7=0

We get rid of parentheses

12x-5x-28-7=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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