10+8(y-2)-y=6y-5(2y-1)

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Solution for 10+8(y-2)-y=6y-5(2y-1) equation: 



10+8(y-2)-y=6y-5(2y-1)

We move all terms to the left:

10+8(y-2)-y-(6y-5(2y-1))=0

We add all the numbers together, and all the variables

-1y+8(y-2)-(6y-5(2y-1))+10=0

We multiply parentheses

-1y+8y-(6y-5(2y-1))-16+10=0



We calculate terms in parentheses: -(6y-5(2y-1)), so:

6y-5(2y-1)

We multiply parentheses

6y-10y+5

We add all the numbers together, and all the variables

-4y+5

Back to the equation:

-(-4y+5)



We add all the numbers together, and all the variables

7y-(-4y+5)-6=0

We get rid of parentheses

7y+4y-5-6=0

We add all the numbers together, and all the variables

11y-11=0

We move all terms containing y to the left, all other terms to the right

11y=11

y=11/11

y=1

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