6a-2(5a-4)=10a+3(2a+9)

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Solution for 6a-2(5a-4)=10a+3(2a+9) equation: 



6a-2(5a-4)=10a+3(2a+9)

We move all terms to the left:

6a-2(5a-4)-(10a+3(2a+9))=0

We multiply parentheses

6a-10a-(10a+3(2a+9))+8=0



We calculate terms in parentheses: -(10a+3(2a+9)), so:

10a+3(2a+9)

We multiply parentheses

10a+6a+27

We add all the numbers together, and all the variables

16a+27

Back to the equation:

-(16a+27)



We add all the numbers together, and all the variables

-4a-(16a+27)+8=0

We get rid of parentheses

-4a-16a-27+8=0

We add all the numbers together, and all the variables

-20a-19=0

We move all terms containing a to the left, all other terms to the right

-20a=19

a=19/-20

a=-19/20

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