0.8(y+0.5)+2.4y=1.2(y-5)

Solution for 0.8(y+0.5)+2.4y=1.2(y-5) equation:

0.8(y+0.5)+2.4y=1.2(y-5)

We move all terms to the left:

0.8(y+0.5)+2.4y-(1.2(y-5))=0

We add all the numbers together, and all the variables

2.4y+0.8(y+0.5)-(1.2(y-5))=0

We multiply parentheses

2.4y+0.8y-(1.2(y-5))+0.4=0


We calculate terms in parentheses: -(1.2(y-5)), so:

1.2(y-5)

We multiply parentheses

1.2y-6

Back to the equation:

-(1.2y-6)


We add all the numbers together, and all the variables

3.2y-(1.2y-6)+0.4=0

We get rid of parentheses

3.2y-1.2y+6+0.4=0

We add all the numbers together, and all the variables

2y+6.4=0

We move all terms containing y to the left, all other terms to the right

2y=-6.4

y=-6.4/2

y=-3+0.4/2