3(x-4)=7(x+7)-13

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Solution for 3(x-4)=7(x+7)-13 equation: 



3(x-4)=7(x+7)-13

We move all terms to the left:

3(x-4)-(7(x+7)-13)=0

We multiply parentheses

3x-(7(x+7)-13)-12=0



We calculate terms in parentheses: -(7(x+7)-13), so:

7(x+7)-13

We multiply parentheses

7x+49-13

We add all the numbers together, and all the variables

7x+36

Back to the equation:

-(7x+36)



We get rid of parentheses

3x-7x-36-12=0

We add all the numbers together, and all the variables

-4x-48=0

We move all terms containing x to the left, all other terms to the right

-4x=48

x=48/-4

x=-12

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