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2x^2-15x=-x2
We move all terms to the left:
2x^2-15x-(-x2)=0
We add all the numbers together, and all the variables
2x^2-(-1x^2)-15x=0
We get rid of parentheses
2x^2+1x^2-15x=0
We add all the numbers together, and all the variables
3x^2-15x=0
a = 3; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·3·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*3}=\frac{30}{6} =5 $
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