4(1y+7)=40=

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Solution for 4(1y+7)=40= equation:



4(1y+7)=40=
We move all terms to the left:
4(1y+7)-(40)=0
We add all the numbers together, and all the variables
4(y+7)-40=0
We multiply parentheses
4y+28-40=0
We add all the numbers together, and all the variables
4y-12=0
We move all terms containing y to the left, all other terms to the right
4y=12
y=12/4
y=3

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