-4(b+1)+2b=3(2b-1)=

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Solution for -4(b+1)+2b=3(2b-1)= equation: 



-4(b+1)+2b=3(2b-1)=

We move all terms to the left:

-4(b+1)+2b-(3(2b-1))=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3(2b-1))=0

We multiply parentheses

2b-4b-(3(2b-1))-4=0



We calculate terms in parentheses: -(3(2b-1)), so:

3(2b-1)

We multiply parentheses

6b-3

Back to the equation:

-(6b-3)



We add all the numbers together, and all the variables

-2b-(6b-3)-4=0

We get rid of parentheses

-2b-6b+3-4=0

We add all the numbers together, and all the variables

-8b-1=0

We move all terms containing b to the left, all other terms to the right

-8b=1

b=1/-8

b=-1/8

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