(2j+8)+(2j)+(j)=108

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Solution for (2j+8)+(2j)+(j)=108 equation:



(2j+8)+(2j)+(j)=108
We move all terms to the left:
(2j+8)+(2j)+(j)-(108)=0
We add all the numbers together, and all the variables
3j+(2j+8)-108=0
We get rid of parentheses
3j+2j+8-108=0
We add all the numbers together, and all the variables
5j-100=0
We move all terms containing j to the left, all other terms to the right
5j=100
j=100/5
j=20

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