-2(2x-3)=3(x+1)+10=

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Solution for -2(2x-3)=3(x+1)+10= equation: 



-2(2x-3)=3(x+1)+10=

We move all terms to the left:

-2(2x-3)-(3(x+1)+10)=0

We multiply parentheses

-4x-(3(x+1)+10)+6=0



We calculate terms in parentheses: -(3(x+1)+10), so:

3(x+1)+10

We multiply parentheses

3x+3+10

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We get rid of parentheses

-4x-3x-13+6=0

We add all the numbers together, and all the variables

-7x-7=0

We move all terms containing x to the left, all other terms to the right

-7x=7

x=7/-7

x=-1

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