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1-121x^2=0
a = -121; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-121)·1
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22}{2*-121}=\frac{-22}{-242} =1/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22}{2*-121}=\frac{22}{-242} =-1/11 $
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