2/5x-5=1/5(7x+10

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Solution for 2/5x-5=1/5(7x+10 equation: 



2/5x-5=1/5(7x+10

We move all terms to the left:

2/5x-5-(1/5(7x+10)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 5(7x+10)-5!=0

We move all terms containing x to the left, all other terms to the right

5(7x+10)!=5

x∈R



We calculate fractions


(10x(7-5)/(25x^2(7-5)+(-(1*5x)/(25x^2(7-5)=0



We calculate terms in parentheses: +(10x(7-5)/(25x^2(7-5)+(-(1*5x)/(25x^2(7-5), so:

10x(7-5)/(25x^2(7-5)+(-(1*5x)/(25x^2(7-5

We can not solve this equation

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