5(2z+4)=7(z-8)

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Solution for 5(2z+4)=7(z-8) equation: 



5(2z+4)=7(z-8)

We move all terms to the left:

5(2z+4)-(7(z-8))=0

We multiply parentheses

10z-(7(z-8))+20=0



We calculate terms in parentheses: -(7(z-8)), so:

7(z-8)

We multiply parentheses

7z-56

Back to the equation:

-(7z-56)



We get rid of parentheses

10z-7z+56+20=0

We add all the numbers together, and all the variables

3z+76=0

We move all terms containing z to the left, all other terms to the right

3z=-76

z=-76/3

z=-25+1/3

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