(4x-2)*(4x-2)=(2x+3)(8x-5)

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Solution for (4x-2)*(4x-2)=(2x+3)(8x-5) equation: 



(4x-2)(4x-2)=(2x+3)(8x-5)

We move all terms to the left:

(4x-2)(4x-2)-((2x+3)(8x-5))=0

We multiply parentheses ..

(+16x^2-8x-8x+4)-((2x+3)(8x-5))=0



We calculate terms in parentheses: -((2x+3)(8x-5)), so:

(2x+3)(8x-5)

We multiply parentheses ..

(+16x^2-10x+24x-15)

We get rid of parentheses

16x^2-10x+24x-15

We add all the numbers together, and all the variables

16x^2+14x-15

Back to the equation:

-(16x^2+14x-15)



We get rid of parentheses

16x^2-16x^2-8x-8x-14x+4+15=0

We add all the numbers together, and all the variables

-30x+19=0

We move all terms containing x to the left, all other terms to the right

-30x=-19

x=-19/-30

x=19/30

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