4(x-2)=3(x-4)+2x

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Solution for 4(x-2)=3(x-4)+2x equation: 



4(x-2)=3(x-4)+2x

We move all terms to the left:

4(x-2)-(3(x-4)+2x)=0

We multiply parentheses

4x-(3(x-4)+2x)-8=0



We calculate terms in parentheses: -(3(x-4)+2x), so:

3(x-4)+2x

We add all the numbers together, and all the variables

2x+3(x-4)

We multiply parentheses

2x+3x-12

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

4x-5x+12-8=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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