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X-2/3X=14
We move all terms to the left:
X-2/3X-(14)=0
Domain of the equation: 3X!=0We multiply all the terms by the denominator
X!=0/3
X!=0
X∈R
X*3X-14*3X-2=0
Wy multiply elements
3X^2-42X-2=0
a = 3; b = -42; c = -2;
Δ = b2-4ac
Δ = -422-4·3·(-2)
Δ = 1788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1788}=\sqrt{4*447}=\sqrt{4}*\sqrt{447}=2\sqrt{447}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{447}}{2*3}=\frac{42-2\sqrt{447}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{447}}{2*3}=\frac{42+2\sqrt{447}}{6} $
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