-6(x+1)-7x=2(x-3)+1

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Solution for -6(x+1)-7x=2(x-3)+1 equation: 



-6(x+1)-7x=2(x-3)+1

We move all terms to the left:

-6(x+1)-7x-(2(x-3)+1)=0

We add all the numbers together, and all the variables

-7x-6(x+1)-(2(x-3)+1)=0

We multiply parentheses

-7x-6x-(2(x-3)+1)-6=0



We calculate terms in parentheses: -(2(x-3)+1), so:

2(x-3)+1

We multiply parentheses

2x-6+1

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

-13x-(2x-5)-6=0

We get rid of parentheses

-13x-2x+5-6=0

We add all the numbers together, and all the variables

-15x-1=0

We move all terms containing x to the left, all other terms to the right

-15x=1

x=1/-15

x=-1/15

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