7y(y-8)=0

Solution for 7y(y-8)=0 equation:

7y(y-8)=0

We multiply parentheses

7y^2-56y=0

a = 7; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·7·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*7}=\frac{0}{14}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*7}=\frac{112}{14}
=8
$