5x(32/5x)=5x*4

Solution for 5x(32/5x)=5x*4 equation:

5x(32/5x)=5x*4

We move all terms to the left:

5x(32/5x)-(5x*4)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5x(+32/5x)-(+5x*4)=0

We multiply parentheses

160x^2-(+5x*4)=0

We get rid of parentheses

160x^2-5x*4=0

Wy multiply elements

160x^2-20x=0

a = 160; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·160·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*160}=\frac{0}{320}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*160}=\frac{40}{320}
=1/8
$