4n+3(n-9)=3n+2(n-1)

Solution for 4n+3(n-9)=3n+2(n-1) equation:

4n+3(n-9)=3n+2(n-1)

We move all terms to the left:

4n+3(n-9)-(3n+2(n-1))=0

We multiply parentheses

4n+3n-(3n+2(n-1))-27=0


We calculate terms in parentheses: -(3n+2(n-1)), so:

3n+2(n-1)

We multiply parentheses

3n+2n-2

We add all the numbers together, and all the variables

5n-2

Back to the equation:

-(5n-2)


We add all the numbers together, and all the variables

7n-(5n-2)-27=0

We get rid of parentheses

7n-5n+2-27=0

We add all the numbers together, and all the variables

2n-25=0

We move all terms containing n to the left, all other terms to the right

2n=25

n=25/2

n=12+1/2