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100=(2x)2
We move all terms to the left:
100-((2x)2)=0
determiningTheFunctionDomain -2x2+100=0
We add all the numbers together, and all the variables
-2x^2+100=0
a = -2; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-2)·100
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{2}}{2*-2}=\frac{0-20\sqrt{2}}{-4} =-\frac{20\sqrt{2}}{-4} =-\frac{5\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{2}}{2*-2}=\frac{0+20\sqrt{2}}{-4} =\frac{20\sqrt{2}}{-4} =\frac{5\sqrt{2}}{-1} $
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