3(2v-9)=3-2(v-5)

Solution for 3(2v-9)=3-2(v-5) equation:

3(2v-9)=3-2(v-5)

We move all terms to the left:

3(2v-9)-(3-2(v-5))=0

We multiply parentheses

6v-(3-2(v-5))-27=0


We calculate terms in parentheses: -(3-2(v-5)), so:

3-2(v-5)

determiningTheFunctionDomain
-2(v-5)+3

We multiply parentheses

-2v+10+3

We add all the numbers together, and all the variables

-2v+13

Back to the equation:

-(-2v+13)


We get rid of parentheses

6v+2v-13-27=0

We add all the numbers together, and all the variables

8v-40=0

We move all terms containing v to the left, all other terms to the right

8v=40

v=40/8

v=5