3k-2(k+12)=11

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Solution for 3k-2(k+12)=11 equation: 



3k-2(k+12)=11

We move all terms to the left:

3k-2(k+12)-(11)=0

We multiply parentheses

3k-2k-24-11=0

We add all the numbers together, and all the variables

k-35=0

We move all terms containing k to the left, all other terms to the right

k=35

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